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Theoretical Foundations of Computer Science
Lattices of sets and algebraic closure operator
I. A. Gorbunov Tver State University, Tver
Abstract:
It is well known that a lattice of closed sets is algebraic lattice if a closure operator is algebraic. The converse is not true. In this paper we give an example of an algebraic lattice the closure operator of which is not algebraic.
The exact criterion that the closure operator of an algebraic lattice is algebraic is found. It is proved that the closure operator of an algebraic lattice ${\mathcal T}$ is algebraic if and only if for any $X\in{\mathcal T}$ and for any
$x\in X$, there exists a compact element $K_x$ such that $x\in K_x$ and $K_x\subseteq X$.
Keywords:
algebraic lattice, algebraic closure operator, closure system.
Received: 29.06.2017 Revised: 12.09.2017
Citation:
I. A. Gorbunov, “Lattices of sets and algebraic closure operator”, Vestnik TVGU. Ser. Prikl. Matem. [Herald of Tver State University. Ser. Appl. Math.], 2017, no. 4, 35–42
Linking options:
https://www.mathnet.ru/eng/vtpmk187 https://www.mathnet.ru/eng/vtpmk/y2017/i4/p35
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Abstract page: | 237 | Full-text PDF : | 221 | References: | 25 |
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