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Ural Mathematical Journal, 2021, Volume 7, Issue 2, Pages 86–93
DOI: https://doi.org/10.15826/umj.2021.2.006
(Mi umj151)
 

Note on super $(a,1)-P_{3}$-antimagic total labeling of star $S_n$

S. Rajkumar, M. Nalliah, Madhu Venkataraman

Department of Mathematics, School of Advanced Sciences, Vellore Institute of Technology
References:
Abstract: Let $G=(V, E)$ be a simple graph and $H$ be a subgraph of $G$. Then $G$ admits an $H$-covering, if every edge in $E(G)$ belongs to at least one subgraph of $G$ that is isomorphic to $H$. An $(a,d)-H$-antimagic total labeling of $G$ is bijection $f:V(G)\cup E(G)\rightarrow \{1, 2, 3,\dots, |V(G)| + |E(G)|\}$ such that for all subgraphs $ H'$ of $G$ isomorphic to $H$, the $H'$ weights $w(H') =\sum_{v\in V(H')} f (v) + \sum_{e\in E(H')} f (e)$ constitute an arithmetic progression $\{a, a + d, a + 2d, \dots , a + (n- 1)d\}$, where $a$ and $d$ are positive integers and $n$ is the number of subgraphs of $G$ isomorphic to $H$. The labeling $f$ is called a super $(a, d)-H$-antimagic total labeling if $f(V(G))=\{1, 2, 3,\dots, |V(G)|\}.$ In [5], David Laurence and Kathiresan posed a problem that characterizes the super $ (a, 1)-P_{3}$-antimagic total labeling of Star $S_{n},$ where $n=6,7,8,9.$ In this paper, we completely solved this problem.
Keywords: $H$-covering, super $(a,d)-H$-antimagic, star.
Bibliographic databases:
Document Type: Article
Language: English
Citation: S. Rajkumar, M. Nalliah, Madhu Venkataraman, “Note on super $(a,1)-P_{3}$-antimagic total labeling of star $S_n$”, Ural Math. J., 7:2 (2021), 86–93
Citation in format AMSBIB
\Bibitem{RajNalVen21}
\by S.~Rajkumar, M.~Nalliah, Madhu~Venkataraman
\paper Note on super $(a,1)-P_{3}$-antimagic total labeling of star $S_n$
\jour Ural Math. J.
\yr 2021
\vol 7
\issue 2
\pages 86--93
\mathnet{http://mi.mathnet.ru/umj151}
\crossref{https://doi.org/10.15826/umj.2021.2.006}
\mathscinet{http://mathscinet.ams.org/mathscinet-getitem?mr=MR4358915}
\elib{https://elibrary.ru/item.asp?id=47556643 }
\scopus{https://www.scopus.com/record/display.url?origin=inward&eid=2-s2.0-85124958262}
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