Abstract:
Suppose the normalizer NN of a subgroup AA of a simple group GG is a Frobenius group with kernel AA, and the intersection of AA with any other conjugate subgroup of GG is trivial, and suppose, if AA is elementary Abelian, that |A|>2n+1|A|>2n+1, where n=|N:A|n=|N:A|. It is proved that if AA has a complement BB in GG, then GG acts doubly transitively on the set of right cosets of GG modulo BB, the subgroup BB is maximal in GG, and |B||B| is divisible by |A|−1|A|−1. The proof makes essential use of the coherence of a certain set of irreducible characters of NN.