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Diskretnaya Matematika, 2009, Volume 21, Issue 4, Pages 95–104
DOI: https://doi.org/10.4213/dm1075
(Mi dm1075)
 

Defragmentation of permutation tables with four columns

A. M. Magomedov
References:
Abstract: We consider a table with columns each of which contains each symbol of an alphabet $A$ precisely once; the remaining elements of a column are equal to zero. It is required to transform the table preserving the sets of elements in each row and each column to the form with consecutively placed elements of alphabet $A$ in each row. We give conditions for solvability of this problem.
Received: 25.11.2008
English version:
Discrete Mathematics and Applications, 2009, Volume 19, Issue 5, Pages 523–532
DOI: https://doi.org/10.1515/DMA.2009.035
Bibliographic databases:
Document Type: Article
UDC: 519.618
Language: Russian
Citation: A. M. Magomedov, “Defragmentation of permutation tables with four columns”, Diskr. Mat., 21:4 (2009), 95–104; Discrete Math. Appl., 19:5 (2009), 523–532
Citation in format AMSBIB
\Bibitem{Mag09}
\by A.~M.~Magomedov
\paper Defragmentation of permutation tables with four columns
\jour Diskr. Mat.
\yr 2009
\vol 21
\issue 4
\pages 95--104
\mathnet{http://mi.mathnet.ru/dm1075}
\crossref{https://doi.org/10.4213/dm1075}
\mathscinet{http://mathscinet.ams.org/mathscinet-getitem?mr=2641022}
\elib{https://elibrary.ru/item.asp?id=20730315}
\transl
\jour Discrete Math. Appl.
\yr 2009
\vol 19
\issue 5
\pages 523--532
\crossref{https://doi.org/10.1515/DMA.2009.035}
\scopus{https://www.scopus.com/record/display.url?origin=inward&eid=2-s2.0-75349109273}
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  • https://www.mathnet.ru/eng/dm/v21/i4/p95
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