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$\mathbb Q$-completions of free solvable groups
Ch. K. Guptaa, N. S. Romanovskiibc a Dep. Math., Univ. Manitoba, Winnipeg, R3T 2N2, Canada
b Novosibirsk State University, ul. Pirogova 2, Novosibirsk, 630090, Russia
c Sobolev Institute of Mathematics, pr. Akad. Koptyuga 4, Novosibirsk, 630090, Russia
Abstract:
A group $G$ is said to be complete if, for any natural $n$ and any element $g\in G$, an equation $x^n=g$ is solvable in $G$. If every such equation in the group has at most one solution, then we say that the condition for uniqueness of root extraction is satisfied. A complete group with unique root extraction can be treated as a $\mathbb Q$-power group since it admits an operation of raising an element to any rational power. Let a group $G$ be embedded in a complete group $H$ with unique root extraction, and let $H$ be generated as a $\mathbb Q$-group by the set $G$. Then $H$ is called a $\mathbb Q$-completion of $G$.
We prove that every $m$-rigid group $G$ is independently embedded in a complete $m$-rigid group. Under the specified condition for independence of an embedding, the $\mathbb Q$-completion of the group $G$ in the class of rigid groups is defined uniquely up to $G$-isomorphism. It is stated that the centralizer of any element of an independent $\mathbb Q$-completion of a free solvable group which does not belong to the last nontrivial member of a rigid series of this completion is isomorphic to the additive group of a field $\mathbb Q$ of rational numbers.
Keywords:
$m$-rigid group, free solvable group, $\mathbb Q$-completion.
Received: 23.01.2015
Citation:
Ch. K. Gupta, N. S. Romanovskii, “$\mathbb Q$-completions of free solvable groups”, Algebra Logika, 54:2 (2015), 193–211; Algebra and Logic, 54:2 (2015), 127–139
Linking options:
https://www.mathnet.ru/eng/al687 https://www.mathnet.ru/eng/al/v54/i2/p193
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Abstract page: | 268 | Full-text PDF : | 41 | References: | 39 | First page: | 15 |
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